A bag contains 7 black and 5 white balls. A b | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Total number of balls in the bag $= 7 + 5 = 12$.Since the ball is replaced after the first draw,the total number of balls remains $12$ for the sec

Vedclass · Accepted Answer

$\frac{35}{144}$

Vedclass · Answer

(A) Total number of balls in the bag $= 7 + 5 = 12$.Since the ball is replaced after the first draw,the total number of balls remains $12$ for the second draw.The probability of drawing a black ball in the first draw is $P(B_1) = \frac{7}{12}$.The probability of drawing a white ball in the second draw is $P(W_2) = \frac{5}{12}$.Since these are independent events,the probability that the first ball is black and the second is white is $P(B_1 \cap W_2) = P(B_1) 	imes P(W_2) = \frac{7}{12} 	imes \frac{5}{12} = \frac{35}{144}$.

$A$ bag contains $7$ black and $5$ white balls. $A$ ball is drawn out and replaced in the bag. Then a ball is drawn again. What is the probability that the first ball was black and the second white?

Similar Questions

If the probabilities of a boy and a girl being born are the same,then in a $4$ children family,the probability of having at least one girl is:

$A$ determinant is chosen at random from the set of all determinants of order $2$ with elements $0$ or $1$ only. The probability that the determinant chosen is non-zero is

For two events $A$ and $B$,if $P(A) = P(A|B) = 1/4$ and $P(B|A) = 1/2$,then

$A$ mapping is selected at random from the set of all the mappings of the set $A = \{1, 2, ..., n\}$ into itself. The probability that the mapping selected is an injection is

One ticket is drawn at random out of $30$ tickets numbered from $1$ to $30.$ Find the probability that the number on the ticket is a multiple of $5$ or $7.$

Vedclass Test Series

Exam Paper Generator

Online Exam Module