$A$ bag contains $5$ white, $7$ red, and $8$ black balls. If four balls are drawn one by one without replacement, what is the probability that all are white?
- A$\frac{1}{969}$
- B$\frac{1}{380}$
- C$\frac{5}{20}$
- DNone of these
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View Solution$A$ bag contains $4$ red, $3$ white, and $5$ blue balls. Three balls are drawn at a time randomly from the bag. Match the items from List-$I$ with those of List-$II$.
List-$I$ List-$II$ $A$. Probability of getting $1$ red, $1$ white and $1$ blue ball $(i)$ $\frac{3}{44}$ $B$. Probability of getting $2$ white and $1$ blue ball $(ii)$ $\frac{21}{55}$ $C$. Probability of getting $2$ red and $1$ white ball $(iii)$ $\frac{38}{55}$ $D$. Probability that none of the balls is white $(iv)$ $\frac{3}{11}$ $(v)$ $\frac{9}{110}$
| List-$I$ | List-$II$ |
| $A$. Probability of getting $1$ red, $1$ white and $1$ blue ball | $(i)$ $\frac{3}{44}$ |
| $B$. Probability of getting $2$ white and $1$ blue ball | $(ii)$ $\frac{21}{55}$ |
| $C$. Probability of getting $2$ red and $1$ white ball | $(iii)$ $\frac{38}{55}$ |
| $D$. Probability that none of the balls is white | $(iv)$ $\frac{3}{11}$ |
| $(v)$ $\frac{9}{110}$ |
$A$ bag contains $6$ red,$5$ white and $4$ black balls. Two balls are drawn. The probability that none of them is red,is
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