A bag contains 4 white,5 red and 6 black ball | vedclass

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(A) Total number of balls $= 4 + 5 + 6 = 15$. Number of ways to draw $2$ balls from $15$ is $^{15}C_2 = \frac{15 	imes 14}{2} = 105$. We want the pro

Vedclass · Accepted Answer

$\frac{44}{105}$

Vedclass · Answer

(A) Total number of balls $= 4 + 5 + 6 = 15$. Number of ways to draw $2$ balls from $15$ is $^{15}C_2 = \frac{15 	imes 14}{2} = 105$. We want the probability that exactly one ball is white. This means one ball is white and the other is non-white (red or black). Number of white balls $= 4$. Number of non-white balls $= 5 + 6 = 11$. Number of ways to choose $1$ white ball and $1$ non-white ball $= ^4C_1 	imes ^{11}C_1 = 4 	imes 11 = 44$. Required probability $= \frac{44}{105}$.

$A$ bag contains $4$ white,$5$ red and $6$ black balls. If two balls are drawn at random,then the probability that one of them is white is

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