A bag contains 5 brown and 4 white socks. A m | vedclass

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(D) Total number of socks $= 5 + 4 = 9$.The total number of ways to select $2$ socks out of $9$ is given by $^9C_2 = \frac{9 	imes 8}{2 	imes 1} = 3

Vedclass · Accepted Answer

$\frac{48}{108}$

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(D) Total number of socks $= 5 + 4 = 9$.The total number of ways to select $2$ socks out of $9$ is given by $^9C_2 = \frac{9 	imes 8}{2 	imes 1} = 36$.The number of ways to select $2$ brown socks is $^5C_2 = \frac{5 	imes 4}{2 	imes 1} = 10$.The number of ways to select $2$ white socks is $^4C_2 = \frac{4 	imes 3}{2 	imes 1} = 6$.The probability that both socks are of the same colour is $P(	ext{Both brown or both white}) = \frac{^5C_2 + ^4C_2}{^9C_2} = \frac{10 + 6}{36} = \frac{16}{36}$.To match the given options,we multiply the numerator and denominator by $3$: $\frac{16 	imes 3}{36 	imes 3} = \frac{48}{108}$.

$A$. Probability that none of the balls is white	$I$. $\frac{1}{70}$
$B$. Probability of getting $2$ white and $1$ blue ball	$II$. $\frac{6}{35}$
$C$. Probability of getting $2$ blue and $1$ white ball	$III$. $\frac{13}{20}$
$D$. Probability of getting $1$ red, $1$ white and $1$ blue ball	$IV$. $\frac{1}{10}$

$A$ bag contains $5$ brown and $4$ white socks. $A$ man pulls out two socks. The probability that these are of the same colour is

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