A bag contains 8 red and 7 black balls. Two b | vedclass

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(C) Total number of balls = $8 + 7 = 15$. Number of ways to draw $2$ balls from $15$ is $^{15}C_2 = \frac{15 	imes 14}{2 	imes 1} = 105$. For both b

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$\frac{7}{15}$

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(C) Total number of balls = $8 + 7 = 15$. Number of ways to draw $2$ balls from $15$ is $^{15}C_2 = \frac{15 	imes 14}{2 	imes 1} = 105$. For both balls to be of the same colour,they must either both be red or both be black. Number of ways to choose $2$ red balls = $^8C_2 = \frac{8 	imes 7}{2 	imes 1} = 28$. Number of ways to choose $2$ black balls = $^7C_2 = \frac{7 	imes 6}{2 	imes 1} = 21$. Total favorable outcomes = $28 + 21 = 49$. Required probability = $\frac{49}{105} = \frac{7}{15}$.

$A$ bag contains $8$ red and $7$ black balls. Two balls are drawn at random. The probability that both the balls are of the same colour is

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