(B) To ensure that we have at least two balls of the same colour,we apply the Pigeonhole Principle.If we draw $1$ ball,it can be either black or white

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(B) To ensure that we have at least two balls of the same colour,we apply the Pigeonhole Principle.If we draw $1$ ball,it can be either black or white.If we draw $2$ balls,they could be one black and one white (different colours).If we draw $3$ balls,according to the Pigeonhole Principle,since there are only $2$ colours available,at least $2$ balls must be of the same colour.Therefore,the minimum number of balls required is $3$.

Competitive Quantitative Aptitude Permutation and Combination Permutation and Combination

Medium

$A$ bag contains balls of two colours,$3$ black and $3$ white. What is the minimum number of balls which must be drawn from the bag,without looking,so that among these there are two of the same colour?

A
$2$
B
$3$
C
$4$
D
$5$

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Permutation and Combination

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Permutation and Combination

How many even numbers of four digits can be formed with the digits $0, 1, 2, 3, 4, 5$ and $6$,if no digit is used more than once?

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$8$-digit numbers are formed using the digits $1, 1, 2, 2, 2, 3, 4, 4$. The number of such numbers in which the odd digits do not occupy odd places is:

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The number of different words that can be formed from the letters of the word $SUCCESS$ in which the two $C$ are together but no two $S$ are together are:

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Let the eleven letters $A, B, \dots, K$ denote an arbitrary permutation of the integers $(1, 2, \dots, 11)$. Then, the product $(A - 1)(B - 2)(C - 3) \dots (K - 11)$ is:

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In how many different ways can the letters of the word '$PRAISE$' be arranged?

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$A$ bag contains balls of two colours,$3$ black and $3$ white. What is the minimum number of balls which must be drawn from the bag,without looking,so that among these there are two of the same colour?

Similar Questions

How many even numbers of four digits can be formed with the digits $0, 1, 2, 3, 4, 5$ and $6$,if no digit is used more than once?

$8$-digit numbers are formed using the digits $1, 1, 2, 2, 2, 3, 4, 4$. The number of such numbers in which the odd digits do not occupy odd places is:

The number of different words that can be formed from the letters of the word $SUCCESS$ in which the two $C$ are together but no two $S$ are together are:

Let the eleven letters $A, B, \dots, K$ denote an arbitrary permutation of the integers $(1, 2, \dots, 11)$. Then, the product $(A - 1)(B - 2)(C - 3) \dots (K - 11)$ is:

In how many different ways can the letters of the word '$PRAISE$' be arranged?

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