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(A) When a balanced die is rolled,the total number of possible outcomes is $S = \{1, 2, 3, 4, 5, 6\}$.The total number of outcomes is $n(S) = 6$.Let $

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$1/3$

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(A) When a balanced die is rolled,the total number of possible outcomes is $S = \{1, 2, 3, 4, 5, 6\}$.The total number of outcomes is $n(S) = 6$.Let $E$ be the event of getting a number smaller than $3$.The favorable outcomes are $E = \{1, 2\}$.The number of favorable outcomes is $n(E) = 2$.The probability $P(E)$ is given by the formula $P(E) = \frac{n(E)}{n(S)}$.Therefore,$P(E) = \frac{2}{6} = \frac{1}{3}$.

$A$ balanced die is rolled. The probability of receiving a number smaller than $3$ is ..... .

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