A ball of mass 0.5, kg moving with a velocity | vedclass

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Question

(A) Given: Mass $m = 0.5\, kg$,initial velocity $u = 2\, m/s$,final velocity $v = -2\, m/s$ (since it bounces back),and time of contact $\Delta t = 1\

Vedclass · Accepted Answer

$2000$

Vedclass · Answer

(A) Given: Mass $m = 0.5\, kg$,initial velocity $u = 2\, m/s$,final velocity $v = -2\, m/s$ (since it bounces back),and time of contact $\Delta t = 1\, ms = 10^{-3}\, s$.According to Newton's second law,the average force $F_{av}$ is the rate of change of momentum:$F_{av} = \frac{\Delta p}{\Delta t} = \frac{m(v - u)}{\Delta t}$$F_{av} = \frac{0.5 	imes (-2 - 2)}{10^{-3}}$$F_{av} = \frac{0.5 	imes (-4)}{10^{-3}} = \frac{-2}{10^{-3}} = -2000\, N$.The magnitude of the average force exerted by the wall on the ball is $2000\, N$.

$A$ ball of mass $0.5\, kg$ moving with a velocity of $2\, m/s$ strikes a wall normally and bounces back with the same speed. If the time of contact between the ball and the wall is $1\, ms$,the average force exerted by the wall on the ball is ......... $N$.

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