A ball of mass 10 , kg moving with a velocity | vedclass

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(B) Initial momentum of the system along the $X$-axis is $P_i = m_1 v_1 = 10 	imes 10 \sqrt{3} = 100 \sqrt{3} \, kg \cdot m/s$.The second ball of mas

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$30$

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(B) Initial momentum of the system along the $X$-axis is $P_i = m_1 v_1 = 10 	imes 10 \sqrt{3} = 100 \sqrt{3} \, kg \cdot m/s$.The second ball of mass $20 \, kg$ splits into two equal pieces of $10 \, kg$ each.Let the velocity of the first piece be $v_y = 10 \, m/s$ along the $Y$-axis and the velocity of the second piece be $v_x = 20 \, m/s$ at an angle $	heta$ with the $X$-axis.Applying the law of conservation of linear momentum along the $X$-axis:$P_{ix} = P_{fx}$$100 \sqrt{3} = (10 	imes v_x \cos 	heta) + (10 	imes 0)$$100 \sqrt{3} = 10 	imes 20 \cos 	heta$$100 \sqrt{3} = 200 \cos 	heta$$\cos 	heta = \frac{100 \sqrt{3}}{200} = \frac{\sqrt{3}}{2}$$	heta = 30^{\circ}$.

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