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(B) The magnetic force $F$ on a charged particle moving in a magnetic field is given by the formula $F = qvB \sin(	heta)$,where $q$ is the charge,$v$

Vedclass · Accepted Answer

Zero

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(B) The magnetic force $F$ on a charged particle moving in a magnetic field is given by the formula $F = qvB \sin(	heta)$,where $q$ is the charge,$v$ is the velocity,$B$ is the magnetic field strength,and $	heta$ is the angle between the velocity vector and the magnetic field vector.Since the alpha particles are moving along (parallel to) the magnetic field,the angle $	heta = 0^\circ$.Therefore,$\sin(0^\circ) = 0$.Consequently,the magnetic force $F = qvB(0) = 0$.Thus,the beam experiences zero magnetic force.

$A$ beam of alpha particles enters a chamber moving along a magnetic field. What is the magnetic force experienced by the beam?

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