A beam of electrons is moving with constant v | vedclass

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(B) Given: Electric field $E = 20 \; V/m$ and magnetic field $B = 0.5 \; T$.The force exerted on an electron by an electric field is $F_e = eE$.The fo

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$40$

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(B) Given: Electric field $E = 20 \; V/m$ and magnetic field $B = 0.5 \; T$.The force exerted on an electron by an electric field is $F_e = eE$.The force exerted on an electron by a magnetic field is $F_m = evB$ (since the velocity is perpendicular to the magnetic field).Since the electron moves with a constant velocity,the net force acting on it must be zero. Therefore,the electric force must balance the magnetic force:$eE = evB$Solving for velocity $v$:$v = \frac{E}{B}$Substituting the given values:$v = \frac{20}{0.5} = 40 \; m/s$.

$A$ beam of electrons is moving with constant velocity in a region having electric and magnetic fields of strength $20 \; Vm^{-1}$ and $0.5 \; T$ at right angles to the direction of motion of the electrons. What is the velocity (in $m/s$) of the electrons?

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