$A$ beam of light $AO$ is incident on a glass slab $(\mu = 1.54)$ in a direction as shown in the figure. The reflected ray $OB$ is passed through a Nicol prism. On viewing through the rotating Nicol prism,we find that $(\tan 57^{\circ} = 1.54)$.

An unpolarized light is incident on the plane interface of an air-dielectric medium as shown in the figure. If the incident angle is equal to the Brewster angle, identify the expression representing the reflected wave.

When the angle of incidence on a material is $60^\circ,$ the reflected light is completely polarized. The velocity of the refracted ray inside the material is (in $m/s$)

When unpolarized light is incident from air onto glass $(\mu = 1.5)$,then:

Given below are two statements:
Statement $I$: If the Brewster's angle for the light propagating from air to glass is $\theta_B$,then Brewster's angle for the light propagating from glass to air is $\frac{\pi}{2} - \theta_B$.
Statement $II$: The Brewster's angle for the light propagating from glass to air is $\tan^{-1}(\mu_g)$ where $\mu_g$ is the refractive index of glass.
In the light of the above statements,choose the correct answer from the options given below:

The polarising angle of a transparent medium is $\theta$. Let the speed of light in the medium be $v$. Then the relation between $\theta$ and $v$ is [where $c$ is the velocity of light in air].