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(A) As the beam of light is incident normally on the face $AB$ of the right-angled prism $ABC$,no refraction occurs at face $AB$. The light passes str

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separate the red colour part from the green and blue colours

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(A) As the beam of light is incident normally on the face $AB$ of the right-angled prism $ABC$,no refraction occurs at face $AB$. The light passes straight and strikes the face $AC$ at an angle of incidence $i = 45^{\circ}$.For total internal reflection to take place at face $AC$,the condition is $i > i_c$,where $i_c$ is the critical angle.We know that $\sin i_c = \frac{1}{\mu}$. Therefore,the condition for total internal reflection is $\sin i > \frac{1}{\mu}$,or $\mu > \frac{1}{\sin i}$.Given $i = 45^{\circ}$,we have $\sin 45^{\circ} = \frac{1}{\sqrt{2}} \approx 0.707$. Thus,the condition becomes $\mu > \sqrt{2} \approx 1.414$.Comparing the refractive indices:For red: $\mu_{	ext{red}} = 1.39 For green: $\mu_{	ext{green}} = 1.44 > 1.414$.For blue: $\mu_{	ext{blue}} = 1.47 > 1.414$.Since $\mu_{	ext{red}} Therefore,the prism will separate the red colour from the green and blue colours.

$A$ beam of light consisting of red,green and blue colours is incident on a right-angled prism. The refractive index of the material of the prism for the above red,green and blue wavelengths are $1.39, 1.44$ and $1.47$ respectively.
The prism will

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$A$ beam of light consisting of red,green and blue colours is incident on a right-angled prism. The refractive index of the material of the prism for the above red,green and blue wavelengths are $1.39, 1.44$ and $1.47$ respectively.The prism will