A binary liquid solution is prepared by mixin | vedclass

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Question

(B) In a mixture of $n$-heptane and ethanol,the intermolecular forces between $n$-heptane and ethanol molecules are weaker than the forces between $n$

Vedclass · Accepted Answer

The solution is non-ideal,showing $+ve$ deviation from Raoult's Law.

Vedclass · Answer

(B) In a mixture of $n$-heptane and ethanol,the intermolecular forces between $n$-heptane and ethanol molecules are weaker than the forces between $n$-heptane$-n$-heptane molecules and ethanol-ethanol molecules.Due to the presence of hydrogen bonding in pure ethanol,the $n$-heptane molecules disrupt these interactions.As a result,the total vapor pressure of the solution is higher than that predicted by Raoult's Law.Therefore,the solution is non-ideal and shows a positive $(+ve)$ deviation from Raoult's Law.

$A$ binary liquid solution is prepared by mixing $n$-heptane and ethanol. Which one of the following statements is correct regarding the behaviour of the solution?

Similar Questions

Liquids $A$ and $B$ form an ideal solution. If $X_A$ and $Y_A$ are the mole fractions of $A$ in the solution and in vapour phase in equilibrium,respectively,then (Given $P_A^{\circ} > P_B^{\circ}$):

For a solution of two liquids $A$ and $B$,if $P = X_A (P_A^o - P_B^o) + P_B^o$ holds true,then what type of solution is it?

For an ideal binary liquid mixture,which of the following conditions is true?

Which of the following is an ideal solution?

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