A black body radiates energy at the rate of E | vedclass

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(A) According to Stefan-Boltzmann Law,the energy radiated per unit area per unit time (emissive power) is proportional to the fourth power of the abso

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$\frac{E}{16}$

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(A) According to Stefan-Boltzmann Law,the energy radiated per unit area per unit time (emissive power) is proportional to the fourth power of the absolute temperature: $E \propto T^4$.Let the initial energy be $E_1 = E$ at temperature $T_1 = T$.Let the final energy be $E_2$ at temperature $T_2 = \frac{T}{2}$.Using the proportionality,we have $\frac{E_2}{E_1} = \left( \frac{T_2}{T_1} \right)^4$.Substituting the values: $\frac{E_2}{E} = \left( \frac{T/2}{T} \right)^4 = \left( \frac{1}{2} \right)^4$.$\frac{E_2}{E} = \frac{1}{16}$.Therefore,$E_2 = \frac{E}{16}$.

$A$ black body radiates energy at the rate of $E \ W/m^2$ at a high temperature $T \ K$. When the temperature is reduced to $\frac{T}{2} \ K$,the radiant energy will be

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