A block of mass 1,kg lies on a horizontal sur | vedclass

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(B) The mass of the block is $m = 1\,kg$ and the acceleration of the truck is $a = 5\,m\,s^{-2}$.The pseudo force acting on the block in the frame of

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$5$

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(B) The mass of the block is $m = 1\,kg$ and the acceleration of the truck is $a = 5\,m\,s^{-2}$.The pseudo force acting on the block in the frame of the truck is $F_{pseudo} = ma = 1 	imes 5 = 5\,N$.The limiting friction force is $f_{max} = \mu_s mg = 0.6 	imes 1 	imes 9.8 = 5.88\,N$.Since the applied pseudo force $(5\,N)$ is less than the limiting friction $(5.88\,N)$,the block remains at rest relative to the truck.Therefore,the static frictional force acting on the block is equal to the applied pseudo force,which is $5\,N$.

$A$ block of mass $1\,kg$ lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is $0.6$. If the acceleration of the truck is $5\,m\,s^{-2}$,the frictional force acting on the block is ........ $N$.

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