(D) Given: $m_1 = 0.50 \ kg$,$u_1 = 2.00 \ m/s$,$m_2 = 1.00 \ kg$,$u_2 = 0 \ m/s$.Since the bodies move together after the collision,it is a perfectly

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(D) Given: $m_1 = 0.50 \ kg$,$u_1 = 2.00 \ m/s$,$m_2 = 1.00 \ kg$,$u_2 = 0 \ m/s$.Since the bodies move together after the collision,it is a perfectly inelastic collision.The formula for energy loss in a perfectly inelastic collision is given by:$\Delta K = \frac{m_1 m_2}{2(m_1 + m_2)} (u_1 - u_2)^2$Substituting the values:$\Delta K = \frac{0.50 \times 1.00}{2(0.50 + 1.00)} (2.00 - 0)^2$$\Delta K = \frac{0.50}{2(1.50)} (4)$$\Delta K = \frac{0.50}{3.00} \times 4 = \frac{2}{3} \approx 0.67 \ J$.

Class 11 Physics Work, Energy and Power Perfectly Inelastic Collision

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$A$ block of mass $0.50 \ kg$ is moving with a speed of $2.00 \ m/s$ on a smooth surface. It strikes another mass of $1.00 \ kg$ at rest and then they move together as a single body. The energy loss during the collision is ............. $J$.

AIEEE 2008 All AIEEE

A
$0.34$
B
$0.16$
C
$1.00$
D
$0.67$

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$A$ block of mass $0.50 \ kg$ is moving with a speed of $2.00 \ m/s$ on a smooth surface. It strikes another mass of $1.00 \ kg$ at rest and then they move together as a single body. The energy loss during the collision is ............. $J$.

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