$A$ body $A$ of mass $M$ while falling vertically downwards under gravity breaks into two parts; a body $B$ of mass $\frac{2}{3} M$ and a body $C$ of mass $\frac{1}{3} M$. The centre of mass of bodies $B$ and $C$ taken together shifts compared to that of body $A$ towards

  • A
    body $C$
  • B
    body $B$
  • C
    depends on height of breaking
  • D
    does not shift

Explore More

Similar Questions

What are some of the notable points in the derivation of $M\vec{A} = \vec{F}_{ext}$?

$A$ man of mass $m$ is suspended in air by holding the rope of a balloon of mass $M$. As the man climbs up the rope,the balloon

Two particles $A$ and $B$,initially at rest,move towards each other under a mutual force of attraction. At the instant when the speed of $A$ is $v$ and the speed of $B$ is $2v$,the speed of the center of mass of the system is:

Show that the total momentum of a system of particles is equal to the product of the total mass of the system and the velocity of the centre of mass.

Two blocks of masses $5 \, kg$ and $2 \, kg$ are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse provides a velocity of $7 \, m/s$ to the heavier block in the direction of the lighter block. The velocity of the centre of mass is ............ $m/s$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo