$A$ body is executing simple harmonic motion with an angular frequency $2\,rad/s$. The velocity of the body at $20\,mm$ displacement,when the amplitude of motion is $60\,mm$,is ...... $mm/s$.

$A$ particle is executing simple harmonic motion. If the force acting on the particle at a position is $86.6 \%$ of the maximum force on it, then the ratio of its velocity at that point and its maximum velocity is

$A$ particle executing $S.H.M.$ starts from the mean position. Its amplitude is $A$ and time period is $T$. At what displacement is its speed one-fourth of the maximum speed?

In case of a simple harmonic motion, if the velocity is plotted along the $X$-axis and the displacement (from the equilibrium position) is plotted along the $Y$-axis, the resultant curve is an ellipse with the ratio:
Major axis (along $X$) $= 20 \pi \times$ Minor axis (along $Y$).
What is the frequency of the simple harmonic motion?

$A$ $1.00 \times 10^{-20} \, kg$ particle is vibrating with simple harmonic motion with a period of $1.00 \times 10^{-5} \, s$ and a maximum speed of $1.00 \times 10^3 \, m/s$. The maximum displacement of the particle is

For a simple harmonic motion given by the equation $x = 5 \sin (4t - \frac{\pi}{6}) \, m$,what is the velocity when its displacement is $3 \, m$ (in $, m/s$)?