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Question

(A) The motion of a body under gravity is symmetric. The time taken to reach the maximum height is $5 	ext{ s}$,so the total time of flight is $10

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$1^{	ext{st}}$ and $10^{	ext{th}}$ second

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(A) The motion of a body under gravity is symmetric. The time taken to reach the maximum height is $5 	ext{ s}$,so the total time of flight is $10 	ext{ s}$.Due to the symmetry of the motion,the distance travelled by the body in any interval of time $t$ during the upward journey is equal to the distance travelled in the corresponding interval of time during the downward journey.Specifically,the distance travelled in the $n^{	ext{th}}$ second of the upward journey is equal to the distance travelled in the $n^{	ext{th}}$ second from the end of the motion (i.e.,the $(10-n+1)^{	ext{th}}$ second).$1$. For $n=1$: Distance in $1^{	ext{st}}$ second = Distance in $10^{	ext{th}}$ second.$2$. For $n=2$: Distance in $2^{	ext{nd}}$ second = Distance in $9^{	ext{th}}$ second.$3$. For $n=4$: Distance in $4^{	ext{th}}$ second = Distance in $7^{	ext{th}}$ second.Comparing this with the given options:- Option $(a)$ is correct ($1^{	ext{st}}$ and $10^{	ext{th}}$ second).- Option $(b)$ is incorrect ($2^{	ext{nd}}$ and $8^{	ext{th}}$ second are not equal).- Option $(c)$ is incorrect ($4^{	ext{th}}$ and $6^{	ext{th}}$ second are not equal).Therefore,the correct answer is $(a)$.

$A$ body is thrown vertically upwards and takes $5 \text{ s}$ to reach maximum height. The distance travelled by the body will be same in

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