A body moves due East with a velocity of 20 , | vedclass

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Question

(D) The body moves in two perpendicular directions: East and North.Let the velocity towards the East be $\vec{v}_1 = 20 \, km/h$ (along the $x$-axis)

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(D) The body moves in two perpendicular directions: East and North.Let the velocity towards the East be $\vec{v}_1 = 20 \, km/h$ (along the $x$-axis) and the velocity towards the North be $\vec{v}_2 = 15 \, km/h$ (along the $y$-axis).The resultant velocity $\vec{v}_R$ is given by the vector sum: $\vec{v}_R = \vec{v}_1 + \vec{v}_2$.Since the vectors are perpendicular,the magnitude of the resultant velocity is calculated using the Pythagorean theorem:$v_R = \sqrt{v_1^2 + v_2^2}$$v_R = \sqrt{20^2 + 15^2}$$v_R = \sqrt{400 + 225}$$v_R = \sqrt{625}$$v_R = 25 \, km/h$.Therefore,the correct option is $D$.

$A$ body moves due East with a velocity of $20 \, km/h$ and then due North with a velocity of $15 \, km/h$. The resultant velocity is .......... $km/h$.

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