A body moves with velocities v,2v,and 3v in t | vedclass

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(C) Let the total distance be $d$. The path is divided into three equal parts,each of distance $d/3$.Time taken for the first part: $t_1 = \frac{d/3}{

Vedclass · Accepted Answer

$\left( \frac{18}{11} \right) v$

Vedclass · Answer

(C) Let the total distance be $d$. The path is divided into three equal parts,each of distance $d/3$.Time taken for the first part: $t_1 = \frac{d/3}{v} = \frac{d}{3v}$.Time taken for the second part: $t_2 = \frac{d/3}{2v} = \frac{d}{6v}$.Time taken for the third part: $t_3 = \frac{d/3}{3v} = \frac{d}{9v}$.Total time $T = t_1 + t_2 + t_3 = \frac{d}{3v} + \frac{d}{6v} + \frac{d}{9v}$.Taking the common denominator as $18v$: $T = \frac{6d + 3d + 2d}{18v} = \frac{11d}{18v}$.Average speed = $\frac{	ext{Total distance}}{	ext{Total time}} = \frac{d}{11d / 18v} = \frac{18v}{11}$.

$A$ body moves with velocities $v$,$2v$,and $3v$ in the first,second,and third one-third distances of the path traveled,respectively. Its average speed is:

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