A constant force overrightarrow F = F_xhat i | vedclass

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Question

(A) Given data:Mass $m = 5\, kg$Initial velocity at $t = 0\, s$ is $\vec{u} = (6\hat i - 2\hat j)\, m/s$Final velocity at $t = 10\, s$ is $\vec{v} = 6

Vedclass · Accepted Answer

$(-3\hat i + 4\hat j)\, N$

Vedclass · Answer

(A) Given data:Mass $m = 5\, kg$Initial velocity at $t = 0\, s$ is $\vec{u} = (6\hat i - 2\hat j)\, m/s$Final velocity at $t = 10\, s$ is $\vec{v} = 6\hat j\, m/s$Acceleration $\vec{a} = \frac{\vec{v} - \vec{u}}{t}$$\vec{a} = \frac{6\hat j - (6\hat i - 2\hat j)}{10} = \frac{-6\hat i + 8\hat j}{10} = (-0.6\hat i + 0.8\hat j)\, m/s^2$According to Newton's second law of motion, force $\vec{F} = m\vec{a}$$\vec{F} = 5 	imes (-0.6\hat i + 0.8\hat j) = (-3\hat i + 4\hat j)\, N$Therefore, the correct option is $A$.

$A$ constant force $\overrightarrow F = F_x\hat i + F_y\hat j$ acts on a body of mass $5\, kg$. At $t = 0\, s$, its velocity is $\overrightarrow v = (6\hat i - 2\hat j)\, m/s$ and at $t = 10\, s$, its velocity is $\overrightarrow v = 6\hat j\, m/s$. Find the force $\overrightarrow F$.

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