A body of mass 1,kg crosses a point O with a | vedclass

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(B) Given: Mass $m = 1\,kg$,initial velocity $u = 60\,ms^{-1}$,and force $F = 10\,N$ directed opposite to the velocity.First,calculate the acceleratio

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$12$

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(B) Given: Mass $m = 1\,kg$,initial velocity $u = 60\,ms^{-1}$,and force $F = 10\,N$ directed opposite to the velocity.First,calculate the acceleration $a$ using Newton's second law,$F = ma$:$a = \frac{F}{m} = \frac{10\,N}{1\,kg} = 10\,ms^{-2}$.Since the force is directed towards $O$ and the body is moving away from $O$,the acceleration is negative relative to the initial velocity: $a = -10\,ms^{-2}$.The time taken to reach the point where velocity becomes zero is $t = \frac{u}{a} = \frac{60}{10} = 6\,s$.The total time taken to return to point $O$ is the time taken to stop plus the time taken to return to the starting point,which is $T = 2t = 2 	imes 6 = 12\,s$.

$A$ body of mass $1\,kg$ crosses a point $O$ with a velocity $60\,ms^{-1}.$ $A$ force of $10\,N$ directed towards $O$ begins to act on it. It will again cross $O$ in ........ $\sec$.

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