A body of mass 8,kg is hanging from another b | vedclass

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(C) Let the masses be $m_1 = 12\,kg$ and $m_2 = 8\,kg$. The acceleration $a = 2.2\,m/s^2$ is upward. Taking $g = 10\,m/s^2$ for standard calculation (

Vedclass · Accepted Answer

$240\,N, 96\,N$

Vedclass · Answer

(C) Let the masses be $m_1 = 12\,kg$ and $m_2 = 8\,kg$. The acceleration $a = 2.2\,m/s^2$ is upward. Taking $g = 10\,m/s^2$ for standard calculation (as $9.8$ leads to non-integer results not matching options).For the $8\,kg$ mass: $T_2 - m_2g = m_2a \implies T_2 - 8(10) = 8(2.2) \implies T_2 = 80 + 17.6 = 97.6\,N$. Using $g = 9.8\,m/s^2$: $T_2 = 8(9.8) + 8(2.2) = 8(12) = 96\,N$.For the $12\,kg$ mass: $T_1 - T_2 - m_1g = m_1a \implies T_1 - 96 - 12(9.8) = 12(2.2) \implies T_1 - 96 - 117.6 = 26.4 \implies T_1 = 240\,N$.Alternatively,for the whole system: $T_1 - (m_1+m_2)g = (m_1+m_2)a \implies T_1 - 20(9.8) = 20(2.2) \implies T_1 = 20(12) = 240\,N$.

$A$ body of mass $8\,kg$ is hanging from another body of mass $12\,kg$. The combination is being pulled upward by a string with an acceleration of $2.2\,m/s^2$. The tensions $T_1$ and $T_2$ will be respectively:

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