A body of mass 5, kg moving with a velocity 1 | vedclass

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Question

(A) According to the law of conservation of linear momentum,the total momentum before the collision is equal to the total momentum after the collision

Vedclass · Accepted Answer

$2.5$

Vedclass · Answer

(A) According to the law of conservation of linear momentum,the total momentum before the collision is equal to the total momentum after the collision.Let $m_1 = 5\, kg$ be the mass of the first body and $u_1 = 10\, m/s$ be its initial velocity.Let $m_2 = 20\, kg$ be the mass of the second body and $u_2 = 0\, m/s$ be its initial velocity.After the collision,the first body comes to rest,so $v_1 = 0\, m/s$.Let $v_2$ be the final velocity of the second body.The conservation equation is: $m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$.Substituting the values: $(5 	imes 10) + (20 	imes 0) = (5 	imes 0) + (20 	imes v_2)$.$50 + 0 = 0 + 20 v_2$.$50 = 20 v_2$.$v_2 = \frac{50}{20} = 2.5\, m/s$.

$A$ body of mass $5\, kg$ moving with a velocity $10\, m/s$ collides with another body of mass $20\, kg$ at rest and comes to rest. The velocity of the second body due to the collision is ............ $m/s$.

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