A body of mass 2, kg moving with a velocity o | vedclass

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Question

(C) According to the law of conservation of linear momentum,the total momentum before the collision is equal to the total momentum after the collision

Vedclass · Accepted Answer

$2/3$

Vedclass · Answer

(C) According to the law of conservation of linear momentum,the total momentum before the collision is equal to the total momentum after the collision.Let the mass of the first body be $m_1 = 2\, kg$ and its velocity be $u_1 = 3\, m/s$.Let the mass of the second body be $m_2 = 1\, kg$ and its velocity be $u_2 = -4\, m/s$ (since it is moving in the opposite direction).Let the common velocity after the collision be $v$.Using the conservation of momentum: $m_1 u_1 + m_2 u_2 = (m_1 + m_2) v$.Substituting the values: $(2 	imes 3) + (1 	imes -4) = (2 + 1) v$.$6 - 4 = 3v$.$2 = 3v$.$v = 2/3\, m/s$.

$A$ body of mass $2\, kg$ moving with a velocity of $3\, m/s$ collides head-on with a body of mass $1\, kg$ moving in the opposite direction with a velocity of $4\, m/s$. After the collision,the two bodies stick together and move with a common velocity. The common velocity in $m/s$ is equal to:

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