(D) The work done by a constant force is given by the formula $W = F S \cos \theta$,where $F$ is the magnitude of the force,$S$ is the displacement,an

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(D) The work done by a constant force is given by the formula $W = F S \cos \theta$,where $F$ is the magnitude of the force,$S$ is the displacement,and $\theta$ is the angle between the force vector and the displacement vector.Given:Force $F = 10\, N$Displacement $S = 4\, m$Angle $\theta = 60^\circ$Substituting these values into the formula:$W = 10 \times 4 \times \cos 60^\circ$Since $\cos 60^\circ = 0.5$,we have:$W = 10 \times 4 \times 0.5 = 20\, J$.Therefore,the work done by the force is $20\, J$.

Class 11 Physics Work, Energy and Power Work Done by Constant Force

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$A$ body of mass $5\, kg$ is placed at the origin and can move only on the $x$-axis. $A$ force of $10\, N$ is acting on it in a direction making an angle of $60^\circ$ with the $x$-axis and displaces it along the $x$-axis by $4\, m$. The work done by the force is $...\, J$.

A
$2.5$
B
$7.25$
C
$40$
D
$20$

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Class 11

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Work, Energy and Power

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Work Done by Constant Force

The work done in pulling up a block of wood weighing $2 \, kN$ for a length of $10 \, m$ on a smooth plane inclined at an angle of $15^\circ$ with the horizontal is ............. $kJ$.

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You lift a heavy book from the floor of the room and keep it in the bookshelf having a height of $2 \, m$. In this process,you take $5 \, s$. The work done by you will depend upon:

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$A$ particle moves from $(1, 0, 3)$ to the point $(-3, 4, 5)$, when a force $F = \hat{i} + 5 \hat{k}$ acts on it. The amount of work done in joules is:

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$A$ force $F = (5\hat i + 3\hat j) \, N$ is applied to a particle,which displaces it from its origin to the point $r = (2\hat i - 1\hat j) \, m$. The work done on the particle is:

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$A$ rope is used to lower a block of mass $M$ vertically downwards by a distance $x$ with a constant downward acceleration of $g/2$. What is the work done by the rope on the block?

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$A$ body of mass $5\, kg$ is placed at the origin and can move only on the $x$-axis. $A$ force of $10\, N$ is acting on it in a direction making an angle of $60^\circ$ with the $x$-axis and displaces it along the $x$-axis by $4\, m$. The work done by the force is $...\, J$.

Similar Questions

The work done in pulling up a block of wood weighing $2 \, kN$ for a length of $10 \, m$ on a smooth plane inclined at an angle of $15^\circ$ with the horizontal is ............. $kJ$.

You lift a heavy book from the floor of the room and keep it in the bookshelf having a height of $2 \, m$. In this process,you take $5 \, s$. The work done by you will depend upon:

$A$ particle moves from $(1, 0, 3)$ to the point $(-3, 4, 5)$, when a force $F = \hat{i} + 5 \hat{k}$ acts on it. The amount of work done in joules is:

$A$ force $F = (5\hat i + 3\hat j) \, N$ is applied to a particle,which displaces it from its origin to the point $r = (2\hat i - 1\hat j) \, m$. The work done on the particle is:

$A$ rope is used to lower a block of mass $M$ vertically downwards by a distance $x$ with a constant downward acceleration of $g/2$. What is the work done by the rope on the block?

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