A body of mass m accelerates uniformly from r | vedclass

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(D) The body starts from rest $(u = 0)$ and accelerates uniformly to $v_1$ in time $t_1$.The acceleration $a$ is given by $a = \frac{v_1 - u}{t_1} = \

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$\frac{mv_1^2t}{t_1^2}$

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(D) The body starts from rest $(u = 0)$ and accelerates uniformly to $v_1$ in time $t_1$.The acceleration $a$ is given by $a = \frac{v_1 - u}{t_1} = \frac{v_1}{t_1}$.At any time $t$,the velocity of the body is $v = at = \left( \frac{v_1}{t_1} ight)t$.The force acting on the body is $F = ma = m \left( \frac{v_1}{t_1} ight)$.The instantaneous power $P$ delivered to the body is $P = F \cdot v$.Substituting the expressions for $F$ and $v$:$P = \left( m \frac{v_1}{t_1} ight) 	imes \left( \frac{v_1}{t_1} t ight) = \frac{mv_1^2t}{t_1^2}$.

$A$ body of mass $m$ accelerates uniformly from rest to $v_1$ in time $t_1$. As a function of time $t$,the instantaneous power delivered to the body is

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