A body weighs 700,gm,wt. on the surface of th | vedclass

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(B) The acceleration due to gravity on the surface of the earth is $g = \frac{GM}{R^2}$.For the planet,the mass $M_p = \frac{M}{7}$ and the radius $R_

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$400$

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(B) The acceleration due to gravity on the surface of the earth is $g = \frac{GM}{R^2}$.For the planet,the mass $M_p = \frac{M}{7}$ and the radius $R_p = \frac{R}{2}$.The acceleration due to gravity on the planet is $g_p = \frac{GM_p}{R_p^2} = \frac{G(M/7)}{(R/2)^2} = \frac{GM/7}{R^2/4} = \frac{4}{7} \frac{GM}{R^2} = \frac{4}{7}g$.The weight of the body on the planet is $W_p = m \cdot g_p = m \cdot (\frac{4}{7}g) = \frac{4}{7} \cdot (mg)$.Given that the weight on earth $W_e = mg = 700\,gm\,wt$.Therefore,$W_p = \frac{4}{7} 	imes 700 = 400\,gm\,wt$.

$A$ body weighs $700\,gm\,wt.$ on the surface of the earth. How much will it weigh on the surface of a planet whose mass is $\frac{1}{7}$ and radius is half of that of the earth?

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