$A$ bomb of $12 \ kg$ divides into two parts whose ratio of masses is $1 : 3$. If the kinetic energy of the smaller part is $216 \ J$,then the momentum of the bigger part in $kg \cdot m/s$ will be:

  • A
    $36$
  • B
    $72$
  • C
    $108$
  • D
    Data is incomplete

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