$A$ bomber plane moves horizontally with a speed of $500\, m/s$ and a bomb released from it strikes the ground in $10\, s$. The angle at which it strikes the ground is $(g = 10\, m/s^2)$.

$A$ bomber plane moves horizontally with a speed of $500\,m/s$ and a bomb released from it,strikes the ground in $10\,s$. The angle with the horizontal at which it strikes the ground will be $(g = 10\,m/s^2)$.

$A$ missile is fired in the horizontal direction from a height of $20\,m$ at a speed of $1000\,m/s$. At what horizontal distance from the base will the missile land?

In the figure shown,find the velocity of the particle at point $P$ $(g = 10\,m/s^2)$.

$A$ gun can fire shells with maximum speed $v_0$ and the maximum horizontal range that can be achieved is $R = \frac{v_0^2}{g}$. If a target farther away by distance $\Delta x$ (beyond $R$) has to be hit with the same gun,show that it could be achieved by raising the gun to a height at least $h = \Delta x \left[ 1 + \frac{\Delta x}{R} \right]$.

$A$ body is projected horizontally from the top of a tower of height $180 \ m$ with a velocity of $20 \ ms^{-1}$. If acceleration due to gravity is $10 \ ms^{-2}$,then match the following:

List-$I$ (Kinematic Variable)	List-$II$ (Value)
$A$. Velocity of the body after $1 \ s$ (in $ms^{-1}$)	$I$. $5$
$B$. Horizontal displacement of the body after $1 \ s$ (in $m$)	$II$. $20$
$C$. Vertical displacement of the body after $1 \ s$ (in $m$)	$III$. $10$
$D$. Vertical velocity of the body after $1 \ s$ (in $ms^{-1}$)	$IV$. $22.4$

The correct answer is