A box contains 4 white pens and 2 black pens. | vedclass

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Question

(C) Total number of pens in the first box = $4 + 2 = 6$.Total number of pens in the second box = $3 + 5 = 8$.The probability of selecting a white pen

Vedclass · Accepted Answer

$\frac{1}{4}$

Vedclass · Answer

(C) Total number of pens in the first box = $4 + 2 = 6$.Total number of pens in the second box = $3 + 5 = 8$.The probability of selecting a white pen from the first box = $\frac{4}{6} = \frac{2}{3}$.The probability of selecting a white pen from the second box = $\frac{3}{8}$.Since the selection from each box is an independent event,the probability that both pens are white is the product of their individual probabilities.Required probability = $\frac{2}{3} 	imes \frac{3}{8} = \frac{6}{24} = \frac{1}{4}$.

$A$ box contains $4$ white pens and $2$ black pens. Another box contains $3$ white pens and $5$ black pens. If one pen is selected from each box,then the probability that both the pens are white is equal to

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