A box contains 10 good articles and 6 with de | vedclass

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(D) Total number of articles in the box $= 10 + 6 = 16$.Let $E$ be the event that the chosen article is either good or has a defect.Since every articl

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$1$

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(D) Total number of articles in the box $= 10 + 6 = 16$.Let $E$ be the event that the chosen article is either good or has a defect.Since every article in the box is either good or defective,the event $E$ is a sure event (sample space).Therefore,the number of favorable outcomes $= 16$.The probability $P(E) = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{16}{16} = 1$.

$A$ box contains $10$ good articles and $6$ with defects. One article is chosen at random. What is the probability that it is either good or has a defect?

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