A box contains 15 black and 20 white balls. W | vedclass

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(C) Total number of balls = $15 + 20 = 35$.Number of ways to select $2$ balls out of $35$ is given by $^{35}C_{2} = \frac{35 	imes 34}{2 	imes 1} =

Vedclass · Accepted Answer

$\frac{60}{119}$

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(C) Total number of balls = $15 + 20 = 35$.Number of ways to select $2$ balls out of $35$ is given by $^{35}C_{2} = \frac{35 	imes 34}{2 	imes 1} = 35 	imes 17 = 595$.We need to select $1$ white ball and $1$ black ball.Number of ways to select $1$ white ball from $20$ is $^{20}C_{1} = 20$.Number of ways to select $1$ black ball from $15$ is $^{15}C_{1} = 15$.Number of favorable outcomes = $^{20}C_{1} 	imes ^{15}C_{1} = 20 	imes 15 = 300$.Probability = $\frac{	ext{Favorable outcomes}}{	ext{Total outcomes}} = \frac{300}{595}$.Dividing both numerator and denominator by $5$,we get $\frac{60}{119}$.

$A$ box contains $15$ black and $20$ white balls. What is the probability that when $2$ balls are selected,one is white?

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