A box contains 2 black,4 white and 3 red ball | vedclass

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Question

(A) Total number of balls = $2 + 4 + 3 = 9$. The probability of drawing $2$ black balls in succession is $\frac{2}{9} 	imes \frac{1}{8}$. The probabi

Vedclass · Accepted Answer

$\frac{1}{1260}$

Vedclass · Answer

(A) Total number of balls = $2 + 4 + 3 = 9$. The probability of drawing $2$ black balls in succession is $\frac{2}{9} 	imes \frac{1}{8}$. The probability of drawing $4$ white balls in succession from the remaining $7$ balls is $\frac{4}{7} 	imes \frac{3}{6} 	imes \frac{2}{5} 	imes \frac{1}{4}$. The probability of drawing $3$ red balls in succession from the remaining $3$ balls is $\frac{3}{3} 	imes \frac{2}{2} 	imes \frac{1}{1} = 1$. The total probability is the product of these probabilities: $P = \frac{2}{9} 	imes \frac{1}{8} 	imes \frac{4}{7} 	imes \frac{3}{6} 	imes \frac{2}{5} 	imes \frac{1}{4} 	imes 1 = \frac{48}{9 	imes 8 	imes 7 	imes 6 	imes 5 	imes 4} = \frac{48}{60480} = \frac{1}{1260}$.

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