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(B) Let the number of one-rupee coins be $x$.According to the problem,the number of $50-paise$ coins is $4x$.Since the number of $50-paise$ coins is d

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$64$

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(B) Let the number of one-rupee coins be $x$.According to the problem,the number of $50-paise$ coins is $4x$.Since the number of $50-paise$ coins is double the number of $25-paise$ coins,the number of $25-paise$ coins is $\frac{4x}{2} = 2x$.The total value of the coins is ₹ $56$.Value of one-rupee coins $= x 	imes 1 = x$.Value of $50-paise$ coins $= 4x 	imes 0.50 = 2x$.Value of $25-paise$ coins $= 2x 	imes 0.25 = 0.5x$.Total value $= x + 2x + 0.5x = 3.5x$.Given $3.5x = 56$,so $x = \frac{56}{3.5} = 16$.The number of $50-paise$ coins is $4x = 4 	imes 16 = 64$.

$A$ box contains ₹ $56$ in the form of coins of one-rupee,$50-paise$ and $25-paise$. The number of $50-paise$ coins is double the number of $25-paise$ coins and four times the number of one-rupee coins. How many $50-paise$ coins are there in the box?

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