A boy playing on the roof of a 10, m high bui | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The boy throws the ball from the roof of a building of height $10\, m$. We need to find the horizontal distance from the throwing point when the b

Vedclass · Accepted Answer

$5\sqrt{3}$

Vedclass · Answer

(D) The boy throws the ball from the roof of a building of height $10\, m$. We need to find the horizontal distance from the throwing point when the ball is at a height of $10\, m$ from the ground. Since the ball is thrown from a height of $10\, m$ and we are looking for the distance when it is again at a height of $10\, m$,this corresponds to the horizontal range of the projectile on a horizontal plane passing through the point of projection. The formula for the horizontal range $R$ is given by: $R = \frac{u^2 \sin(2	heta)}{g}$ Given: Initial speed $u = 10\, m/s$ Angle of projection $	heta = 30^o$ Acceleration due to gravity $g = 10\, m/s^2$ Substituting the values: $R = \frac{(10)^2 \sin(2 	imes 30^o)}{10} = \frac{100 	imes \sin(60^o)}{10} = 10 	imes \frac{\sqrt{3}}{2} = 5\sqrt{3}\, m$ Thus,the ball will be at a distance of $5\sqrt{3}\, m$ from the throwing point.

Similar Questions

The vertical displacement ($y$ in metre) of a projectile in terms of its horizontal displacement ($x$ in metre) is given by $y = (\sqrt{3}x - 0.2x^2)$. The time of flight of the projectile is (Acceleration due to gravity $g = 10 \ ms^{-2}$)

What is the path followed by a moving body,on which a constant force acts in a direction other than the initial velocity (i.e.,excluding parallel and antiparallel directions)?

$A$ heavy particle is projected from a point on the horizontal at an angle $60^\circ$ with the horizontal with a speed of $10 \ m/s$. Then the radius of curvature of its path at the instant of crossing the same horizontal will be ......... $m$.

$A$ stone is thrown vertically at a speed of $30 \,ms^{-1}$ making an angle of $45^{\circ}$ with the horizontal. What is the maximum height reached by the stone (in $\,m$)? Take $g=10 \,ms^{-2}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module