A beaker contains water up to a height h_{1} | vedclass

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(C) The apparent shift produced by a medium of thickness $h$ and refractive index $\mu$ is given by the formula: $\Delta h = h \left( 1 - \frac{1}{\mu

Vedclass · Accepted Answer

$\left( 1 - \frac{1}{\mu_{1}} \right) h_{1} + \left( 1 - \frac{1}{\mu_{2}} \right) h_{2}$

Vedclass · Answer

(C) The apparent shift produced by a medium of thickness $h$ and refractive index $\mu$ is given by the formula: $\Delta h = h \left( 1 - \frac{1}{\mu} \right)$.In this problem,there are two layers: water of height $h_{1}$ with refractive index $\mu_{1}$ and kerosene of height $h_{2}$ with refractive index $\mu_{2}$.The total apparent shift is the sum of the shifts produced by each individual layer:Shift due to water = $h_{1} \left( 1 - \frac{1}{\mu_{1}} \right)$.Shift due to kerosene = $h_{2} \left( 1 - \frac{1}{\mu_{2}} \right)$.Therefore,the total apparent shift = $h_{1} \left( 1 - \frac{1}{\mu_{1}} \right) + h_{2} \left( 1 - \frac{1}{\mu_{2}} \right)$.

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