$A$ bulb of $40 \ W$ is producing light of wavelength $620 \ nm$ with $80 \%$ efficiency. The number of photons emitted by the bulb in $20 \ s$ is $(1 \ eV = 1.6 \times 10^{-19} \ J, hc = 12400 \ eV \ \mathring{A})$

  • A
    $2 \times 10^{18}$
  • B
    $10^{18}$
  • C
    $10^{21}$
  • D
    $2 \times 10^{21}$

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