A bullet of 4 , g mass is fired from a gun of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given:Mass of bullet,$m = 4 \, g = 4 	imes 10^{-3} \, kg$Mass of gun,$M = 4 \, kg$Velocity of bullet relative to ground,$v_b = 50 \, ms^{-1}$Let

Vedclass · Accepted Answer

$0.2 \, kg \, ms^{-1}, 0.05 \, ms^{-1}$

Vedclass · Answer

(C) Given:Mass of bullet,$m = 4 \, g = 4 	imes 10^{-3} \, kg$Mass of gun,$M = 4 \, kg$Velocity of bullet relative to ground,$v_b = 50 \, ms^{-1}$Let $V$ be the recoil velocity of the gun.According to the law of conservation of linear momentum,the initial momentum of the system is zero.$M V + m v_b = 0$$4 	imes V + (4 	imes 10^{-3}) 	imes 50 = 0$$4 V = -0.2$$V = -0.05 \, ms^{-1}$The magnitude of the recoil velocity is $0.05 \, ms^{-1}$.Impulse imparted to the gun is equal to the change in momentum of the gun:$J = |M \Delta V| = |4 	imes (-0.05) - 0| = 0.2 \, kg \, ms^{-1}$.

$A$ bullet of $4 \, g$ mass is fired from a gun of mass $4 \, kg$. If the bullet moves with the muzzle speed of $50 \, ms^{-1}$,the impulse imparted to the gun and the velocity of recoil of the gun are:

Similar Questions

The position-time graph for a particle of mass $100 \ g$ is shown in the figure. The impulse acting on the particle at $t = 5 \ s$ is ............ $N-s$.

$A$ particle of mass $m$ strikes a wall with speed $v$ at an angle $30^{\circ}$ with the wall elastically as shown in the figure. The magnitude of impulse imparted to the ball by the wall is

$A$ ball of mass $0.5 \ kg$ moving horizontally at $10 \ m \ s^{-1}$ strikes a vertical wall and rebounds with speed $v$. The magnitude of the change in linear momentum is found to be $8.0 \ kg \ m \ s^{-1}$. The magnitude of $v$ is, (in $m \ s^{-1}$)

The $F-t$ graph for an object is shown in the figure. What will be the magnitude of the change in momentum $(\Delta p)$ in the interval of $0.03\, s$ from the start?

Vedclass Test Series

Exam Paper Generator

Online Exam Module