A bullet of mass 10 , g is fired with a veloc | vedclass

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(B) According to the law of conservation of linear momentum,the total momentum before firing is equal to the total momentum after firing.Initial momen

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(B) According to the law of conservation of linear momentum,the total momentum before firing is equal to the total momentum after firing.Initial momentum of the system (gun + bullet) = $0$ (since both are at rest).Final momentum of the system = $m 	imes v + M 	imes V$,where $m = 0.01 \, kg$ (mass of bullet),$v = 400 \, m s^{-1}$ (velocity of bullet),$M = 4 \, kg$ (mass of gun),and $V$ is the recoil velocity of the gun.Setting the initial momentum equal to the final momentum:$0 = (0.01 \, kg 	imes 400 \, m s^{-1}) + (4 \, kg 	imes V)$$0 = 4 + 4V$$4V = -4$$V = -1 \, m s^{-1}$.The negative sign indicates that the gun recoils in the direction opposite to the bullet.

$A$ bullet of mass $10 \, g$ is fired with a velocity of $400 \, m s^{-1}$ from a gun of mass $4 \, kg$. What is the recoil velocity of the gun (in $, m s^{-1}$)?

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