A can do a certain work in 12 days. B is 60% | vedclass

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(D) Let the total work be $1$ unit.$A$'s $1$ day's work $= \frac{1}{12}$.Since $B$ is $60\%$ more efficient than $A$,$B$'s efficiency $= 1.60 	imes A

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$\frac{60}{13}$

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(D) Let the total work be $1$ unit.$A$'s $1$ day's work $= \frac{1}{12}$.Since $B$ is $60\%$ more efficient than $A$,$B$'s efficiency $= 1.60 	imes A$'s efficiency.$B$'s $1$ day's work $= 1.60 	imes \frac{1}{12} = \frac{160}{100} 	imes \frac{1}{12} = \frac{8}{5} 	imes \frac{1}{12} = \frac{2}{15}$.$(A + B)$'s $1$ day's work $= \frac{1}{12} + \frac{2}{15} = \frac{5 + 8}{60} = \frac{13}{60}$.Therefore,the time taken by $A$ and $B$ together to complete the work $= \frac{60}{13}$ days.

$A$ can do a certain work in $12$ days. $B$ is $60\%$ more efficient than $A$. How many days will $B$ and $A$ together take to do the same job?

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