A capacitor of 50 ,mu {F} is connected in a c | vedclass

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(C) In a steady state,the capacitor acts as an open circuit,so no current flows through the branch containing the capacitor.The circuit consists of th

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(C) In a steady state,the capacitor acts as an open circuit,so no current flows through the branch containing the capacitor.The circuit consists of three resistors of $2 \, k\Omega$ each connected in series with a $6 \, V$ battery.The total resistance of the circuit is $R_{eq} = 2 \, k\Omega + 2 \, k\Omega + 2 \, k\Omega = 6 \, k\Omega$.The current flowing through the circuit is $I = \frac{V}{R_{eq}} = \frac{6 \, V}{6 \, k\Omega} = 1 \, mA$.The capacitor is connected in parallel with the bottom-most $2 \, k\Omega$ resistor.The potential difference across this resistor is $V_c = I 	imes R = 1 \, mA 	imes 2 \, k\Omega = 2 \, V$.Since the capacitor is in parallel with this resistor,the potential difference across the capacitor is also $2 \, V$.The charge on the capacitor is given by $q = C 	imes V_c$.$q = 50 \,\mu {F} 	imes 2 \, V = 100 \,\mu {C}$.

$A$ capacitor of $50 \,\mu {F}$ is connected in a circuit as shown in the figure. The charge on the upper plate of the capacitor is $......\,\mu {C} .$

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