$A$ capacitor of capacitance $C$ is charged to a potential difference $V_0$. The charging battery is removed and the capacitor is now connected to an uncharged capacitor of unknown capacity. The potential difference across the combination becomes $V$. The unknown capacitance is

  • A
    $C\left( \frac{V_0}{V} \right)$
  • B
    $C\left( \frac{V_0}{V} + 1 \right)$
  • C
    $C\left( \frac{V_0}{V} - 1 \right)$
  • D
    $CV$

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