(D) Initial capacitance is $C = \frac{\epsilon_0 A}{d}$. Initial charge is $Q_i = CV$.When the distance is reduced to half $(d' = d/2)$,the new capaci

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) Initial capacitance is $C = \frac{\epsilon_0 A}{d}$. Initial charge is $Q_i = CV$.When the distance is reduced to half $(d' = d/2)$,the new capacitance becomes $C' = \frac{\epsilon_0 A}{d/2} = 2C$.Since the battery remains connected,the potential across the capacitor remains $V$.The new charge on the capacitor is $Q_f = C'V = 2CV$.The additional charge supplied by the battery is $\Delta Q = Q_f - Q_i = 2CV - CV = CV$.The energy supplied by the battery is $W = \Delta Q \times V = (CV) \times V = CV^2$.

Class 12 Physics Electrostatic Potential and Capacitance Mix Examples - Electric Potential and Capacitance

Easy

$A$ capacitor of capacity $C$ is connected to a battery of potential $V$ in parallel. The distance between its plates is reduced to half at once,while the battery remains connected. Then,the energy supplied by the battery to charge the capacitor to potential $V$ again is:

A
$CV^2/4$
B
$CV^2/2$
C
$3CV^2/4$
D
$CV^2$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Electrostatic Potential and Capacitance

Subtopic

Mix Examples - Electric Potential and Capacitance

In the circuit shown in the figure,the ratio of charges on $5 \mu F$ and $4 \mu F$ capacitors is:

Medium

View Solution

Initially,switch $S$ is connected to position $1$ for a long time as shown in the figure. The net amount of heat generated in the circuit after it is shifted to position $2$ is:

Difficult

View Solution

As shown in the figure,what will be the charge on each capacitor and the potential difference across each,respectively?

Difficult

View Solution

Four capacitors with capacitances $C_1 = 1 \ \mu F, C_2 = 1.5 \ \mu F, C_3 = 2.5 \ \mu F$ and $C_4 = 0.5 \ \mu F$ are connected as shown and are connected to a $30 \ V$ source. The potential difference between points $a$ and $b$ is: (in $V$)

MediumAP EAMCET 2021

View Solution

Four capacitors marked with their capacitances and breakdown voltages are connected as shown in the figure. The maximum $EMF$ of the source,so that no capacitor breaks down,is: (in $kV$)

MediumAP EAMCET 2018

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ capacitor of capacity $C$ is connected to a battery of potential $V$ in parallel. The distance between its plates is reduced to half at once,while the battery remains connected. Then,the energy supplied by the battery to charge the capacitor to potential $V$ again is:

Similar Questions

In the circuit shown in the figure,the ratio of charges on $5 \mu F$ and $4 \mu F$ capacitors is:

Initially,switch $S$ is connected to position $1$ for a long time as shown in the figure. The net amount of heat generated in the circuit after it is shifted to position $2$ is:

As shown in the figure,what will be the charge on each capacitor and the potential difference across each,respectively?

Four capacitors with capacitances $C_1 = 1 \ \mu F, C_2 = 1.5 \ \mu F, C_3 = 2.5 \ \mu F$ and $C_4 = 0.5 \ \mu F$ are connected as shown and are connected to a $30 \ V$ source. The potential difference between points $a$ and $b$ is: (in $V$)

Four capacitors marked with their capacitances and breakdown voltages are connected as shown in the figure. The maximum $EMF$ of the source,so that no capacitor breaks down,is: (in $kV$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module