$A$ capacitor of capacity $C_1$ is charged up to $V$ volt and then connected to an uncharged capacitor of capacity $C_2$. The final potential difference across each will be:
- A$\frac{C_2 V}{C_1 + C_2}$
- B$\left( 1 + \frac{C_2}{C_1} \right) V$
- C$\frac{C_1 V}{C_1 + C_2}$
- D$\left( 1 - \frac{C_2}{C_1} \right) V$
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