A car completes the first half of its journey | vedclass

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(C) Let the total distance of the journey be $2d$. Time taken for the first half of the journey is $t_1 = \frac{d}{v_1}$. Time taken for the second ha

Vedclass · Accepted Answer

$\frac{2v_1 v_2}{v_1 + v_2}$

Vedclass · Answer

(C) Let the total distance of the journey be $2d$. Time taken for the first half of the journey is $t_1 = \frac{d}{v_1}$. Time taken for the second half of the journey is $t_2 = \frac{d}{v_2}$. Average velocity $V_{av} = \frac{	ext{Total distance}}{	ext{Total time}} = \frac{2d}{t_1 + t_2}$. Substituting the values,$V_{av} = \frac{2d}{\frac{d}{v_1} + \frac{d}{v_2}} = \frac{2d}{d(\frac{v_2 + v_1}{v_1 v_2})} = \frac{2v_1 v_2}{v_1 + v_2}$.

$A$ car completes the first half of its journey with a velocity $v_1$ and the rest half with a velocity $v_2$. Then the average velocity of the car for the whole journey is

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