A car of mass 1000 , kg negotiates a banked c | vedclass

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(D) For a car on a frictionless banked road,the condition for safe turning is given by the formula: $	an 	heta = \frac{v^2}{rg}$.Here,the radius $r

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$30$

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(D) For a car on a frictionless banked road,the condition for safe turning is given by the formula: $	an 	heta = \frac{v^2}{rg}$.Here,the radius $r = 90 \, m$,the banking angle $	heta = 45^\circ$,and taking acceleration due to gravity $g = 10 \, m \, s^{-2}$.Rearranging the formula for velocity $v$,we get: $v = \sqrt{rg 	an 	heta}$.Substituting the values: $v = \sqrt{90 	imes 10 	imes 	an 45^\circ}$.Since $	an 45^\circ = 1$,we have $v = \sqrt{900 	imes 1} = 30 \, m \, s^{-1}$.

$A$ car of mass $1000 \, kg$ negotiates a banked curve of radius $90 \, m$ on a frictionless road. If the banking angle is $45^\circ$,the speed of the car is ......... $m \, s^{-1}$.

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