A card is drawn from a pack of 52 cards. If A | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The total number of cards is $n(S) = 52$. Number of diamond cards is $n(A) = 13$,so $P(A) = \frac{13}{52} = \frac{1}{4}$. Number of ace cards is $

Vedclass · Accepted Answer

Independent

Vedclass · Answer

(A) The total number of cards is $n(S) = 52$. Number of diamond cards is $n(A) = 13$,so $P(A) = \frac{13}{52} = \frac{1}{4}$. Number of ace cards is $n(B) = 4$,so $P(B) = \frac{4}{52} = \frac{1}{13}$. The number of ace of diamond cards is $n(A \cap B) = 1$,so $P(A \cap B) = \frac{1}{52}$. Now,check for independence: $P(A) 	imes P(B) = \frac{1}{4} 	imes \frac{1}{13} = \frac{1}{52}$. Since $P(A \cap B) = P(A) 	imes P(B)$,the events $A$ and $B$ are independent.

$A$ card is drawn from a pack of $52$ cards. If $A =$ card is of diamond,$B =$ card is an ace,and $A \cap B =$ card is the ace of diamond,then events $A$ and $B$ are

Similar Questions

Let $E_{1}, E_{2}, E_{3}$ be three mutually exclusive events such that $P(E_{1}) = \frac{2+3p}{6}$,$P(E_{2}) = \frac{2-p}{8}$,and $P(E_{3}) = \frac{1-p}{2}$. If the maximum and minimum values of $p$ are $p_{1}$ and $p_{2}$,then $(p_{1} + p_{2})$ is equal to.

Let $A$ and $B$ be two events such that the probability that exactly one of them occurs is $\frac{2}{5}$ and the probability that $A$ or $B$ occurs is $\frac{1}{2}$,then the probability of both of them occurring together is

Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three persons apply for the same house is

If two fair dice are rolled,then the probability that the sum of the numbers on the upper faces is at least $9$,is

Vedclass Test Series

Exam Paper Generator

Online Exam Module